2x^2=283

Solution for 2x^2=283 equation:

2x^2=283

We move all terms to the left:

2x^2-(283)=0

a = 2; b = 0; c = -283;
Δ = b2-4ac
Δ = 02-4·2·(-283)
Δ = 2264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2264}=\sqrt{4*566}=\sqrt{4}*\sqrt{566}=2\sqrt{566}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{566}}{2*2}=\frac{0-2\sqrt{566}}{4}
=-\frac{2\sqrt{566}}{4}
=-\frac{\sqrt{566}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{566}}{2*2}=\frac{0+2\sqrt{566}}{4}
=\frac{2\sqrt{566}}{4}
=\frac{\sqrt{566}}{2}
$